Compound OLL Examples
Solving OLL with two algs in one look
Lucas Garron; March 18-20, 2006

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Examples

The algs themselves should suggest how to be combined; nevertheless, here are a few examples that should make the idea clear.
Unfortunately, I can't cover every "just in case this happens;" try to extrapolate for yourself.

 Example 1 I encountered exactly this LL during my first speed BLD. Do R' F' L' F R' F' R U' L U R' F R2 U2 on a solved cube to see. If you first turn the cube with y or U, you will notice that this OLL is perfectly positioned for an EC followed by an anti-Sune. EC:(U) r U R' U' r' R U R U' R' Anti-Sune:(U) R U2 R' U' R U' R' Combining the two algs will yield this. Synthesis:(U) r U R' U' r' R U R U' R' R U2 R' U' R U' R' Move-cancelling version:(U) r U R' U' M U R U R' U' R U' R' For speed BLD, of course you must figure out the final position in your head. But don't trace! The cube starts as RFBL for edges and FR-FL-BR-BL for corners (positions of cubies in order of homeposition, clockwise from UF[L], ignoring orientation because we know that will be fixed.) The EC will cycle three edges, all but the F: RFBL > BFRL. The anti-Sune will do a counter-clockwise three-edge cycle, BFRL > LFRB, and switch corners across LL: FR-FL-BR-BL > BL-BR-FL-FR. So, going into PLL you have LFRB and BL-BR-FL-FR (orderings, not cycles). Do note the the cube is rotated at the end.

 Example 2 This is the LL from my fastest speed BLD. I used a mini-ZB alg to do EOLL with placement of the last edge, so there's only CO. Sometimes, I will encounter an EO-only case instead. I'm only including this example to alert you to be prepared for exceptions. Do F' U' F U' F' U2 F2 U F' U F U2 F' on a solved cube to see. In this case, there's only a chameleon... OCLL ("Chameleon"):B L B' R B L' B' R' OLL:B L B' R B L' B' R' Speed BLD: The chameleon doesn't affect edges, so edge ordering (LFRB) transfers directly to PLL. The corners were initially correctly placed, but were permuted with OLL: FL-BL-BR-FR > FL-FR-BL-BR.

 Example 3 You should hopefully recognize this OLL. However, for this example I'll execute it using compound OLL. Do F R U R' U' F' on a solved cube to see. If you first turn the cube with y, you will notice that this OLL is perfectly positioned for an EC followed by an anti-Sune. EC:r U R' U' r' R U R U' R' Headlights:(U) R2' D R' U2 R D' R' U2 R' Combining them yields this lengthy OLL. Now, it may be longer, but for speed BLD, you might find it easier to use that to trace F U R U' R' F'. OLL: r U R' U' r' R U R U' R' y R2' D R' U2 R D' R' U2 R' Speed BLD: I won't go over the explicit cycles, but notice that EOLL and OCLL were separate (due to their algs), so their orderings will be independently affected.

 Example 4 Here's one with a 4-flip that I just picked. Do F2 L2 B L2 F L' B2 U2 B L F on a solved cube to see. This time, it's a straightforward 4-flip and Pi.Notice that the Pi is in standard position; what if it weren't? 4-flip:U M' U' R' U' R U M2' U' R' U r Pi:R U2' R2' U' R2 U' R2' U2' R Combined, we get this long, relatively nice, alg. OLL: U M' U' R' U' R U M2' U' R' U r R U2' R2' U' R2 U' R2' U2' R Speed BLD: The initial cycles were RFLB and FR-FL-BR-BL. The 4-flip sends edges across LL: RFLB > LBRF The pi sends corners across LL: FR-FL-BR-BL > BL-BR-FL-FR And it does a 3-edge cycle: LBRF > FBRL